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[Loc] changes to xlfs for 8/29/2022 (#1661)
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@@ -6331,6 +6331,35 @@ El procesador de consultas estima que la implementación del siguiente índice p
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<target state="translated">Vistas de libro de contabilidad descartadas</target>
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<note></note>
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</trans-unit>
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<trans-unit id="SqlProjectModelNotFound">
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<source>Could not find SQL model from project: {0}.</source>
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<target state="translated">No se ha podido encontrar el modelo SQL del proyecto: {0}.</target>
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<note>.
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Parameters: 0 - projectUri (string) </note>
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</trans-unit>
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<trans-unit id="UnsupportedModelType">
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<source>Unsupported model type: {0}.</source>
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<target state="translated">Tipo de modelo no admitido: {0}.</target>
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<note>.
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Parameters: 0 - type (string) </note>
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</trans-unit>
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<trans-unit id="GetUserDefinedObjectsFromModelFailed">
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<source>Failed to get user defined objects from model.</source>
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<target state="translated">No se han podido obtener los objetos definidos por el usuario del modelo.</target>
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<note></note>
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</trans-unit>
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<trans-unit id="ComputedColumnNeedToBePersistedAndNotNullInPrimaryKeyRuleDescription">
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<source>The computed column with name '{0}' has to be persisted and not nullable to be part of a primary key.</source>
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<target state="translated">La columna calculada con el nombre "{0}" debe ser persistente y no acepta valores NULL para formar parte de una clave principal.</target>
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<note>.
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Parameters: 0 - columnName (string) </note>
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</trans-unit>
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<trans-unit id="ComputedColumnNeedToBePersistedInForeignKeyRuleDescription">
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<source>The computed column with name '{0}' has to be persisted to be part of the foreign key '{1}'.</source>
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<target state="translated">La columna calculada con el nombre "{0}" debe ser persistente para formar parte de la clave externa "{1}".</target>
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<note>.
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Parameters: 0 - columnName (string), 1 - foreignKeyName (string) </note>
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</trans-unit>
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</body>
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</file>
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</xliff>
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